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Mathematical Manipulations for drug dosage [View Printable]
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ojbillions
Group: Member Posts: 7 Joined: Sep 26, 2006
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Hello, I am very much confused about some calculations and would appreciate if anyone out there can bail me out.
How can one calculate the Molar concentration of a drug if one is asked to inject an animal with 5mg/Kg body weight ( assuming the drug is Aluminum sulphate).
If the animal weighs 60g and one is to inject it with 5mg/Kg bodyweight of Aluminum sulphate, what is the molar concentration of the amount of Aluminum sulphate to be injected.
I would very much appreciate your response. Thanks in advance.
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| Posted Sep 11, 2007, 18:11 PM |
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qinglongyanyuedao
Group: Member Posts: 50 Joined: Oct 08, 2006
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hi, here is the way you do the calculations. assuming the Molar concentration of your Aluminum sulphate (Molecular Weight 342) is A, then your w/v concentration would be A*342g/L.
and the total injection of the 60g animal should be (5mg/Kg)*(0.06kg), that is 0.3mg, and which is 0.0003g
so the injection volume (L) will be 0.0003/(A*342). and injection volume (ml) is 0.3/(A*342)
hope it helps
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| Posted Sep 11, 2007, 14:32 PM |
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ojbillions
Group: Member Posts: 7 Joined: Sep 26, 2006
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Oh, thanks a lot for your response. I really appreciate it. | qinglongyanyuedao said: | hi, here is the way you do the calculations. assuming the Molar concentration of your Aluminum sulphate (Molecular Weight 342) is A, then your w/v concentration would be A*342g/L.
and the total injection of the 60g animal should be (5mg/Kg)*(0.06kg), that is 0.3mg, and which is 0.0003g
so the injection volume (L) will be 0.0003/(A*342). and injection volume (ml) is 0.3/(A*342)
I hope it helps |
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| Posted Sep 13, 2007, 1:13 AM |
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